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100d^2-3d=0
a = 100; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·100·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*100}=\frac{0}{200} =0 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*100}=\frac{6}{200} =3/100 $
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